1103330111341 has 2 divisors, whose sum is σ = 1103330111342. Its totient is φ = 1103330111340.

The previous prime is 1103330111311. The next prime is 1103330111423. The reversal of 1103330111341 is 1431110333011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 962576832100 + 140753279241 = 981110^2 + 375171^2 .

It is an emirp because it is prime and its reverse (1431110333011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1103330111341 - 2⁵ = 1103330111309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1103330111311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551665055670 + 551665055671.

It is an arithmetic number, because the mean of its divisors is an integer number (551665055671).

Almost surely, 2^{1103330111341} is an apocalyptic number.

It is an amenable number.

1103330111341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103330111341 is an equidigital number, since it uses as much as digits as its factorization.

1103330111341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1103330111341 its reverse (1431110333011), we get a palindrome (2534440444352).

The spelling of 1103330111341 in words is "one trillion, one hundred three billion, three hundred thirty million, one hundred eleven thousand, three hundred forty-one".