Base | Representation |
---|---|
bin | 10100100011010010… |
… | …01111001101110101 |
3 | 1001110221100212212012 |
4 | 22101221033031311 |
5 | 140044030104031 |
6 | 5022500534005 |
7 | 540263462612 |
oct | 122151171565 |
9 | 31427325765 |
10 | 11033441141 |
11 | 47520a96a8 |
12 | 217b0b1305 |
13 | 106ab359c8 |
14 | 7694d7509 |
15 | 448997b2b |
hex | 291a4f375 |
11033441141 has 2 divisors, whose sum is σ = 11033441142. Its totient is φ = 11033441140.
The previous prime is 11033441119. The next prime is 11033441147. The reversal of 11033441141 is 14114433011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8825850916 + 2207590225 = 93946^2 + 46985^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11033441141 is a prime.
It is a super-2 number, since 2×110334411412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11033441147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516720570 + 5516720571.
It is an arithmetic number, because the mean of its divisors is an integer number (5516720571).
Almost surely, 211033441141 is an apocalyptic number.
It is an amenable number.
11033441141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11033441141 is an equidigital number, since it uses as much as digits as its factorization.
11033441141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 11033441141 its reverse (14114433011), we get a palindrome (25147874152).
The spelling of 11033441141 in words is "eleven billion, thirty-three million, four hundred forty-one thousand, one hundred forty-one".
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