110340004013 has 2 divisors, whose sum is σ = 110340004014. Its totient is φ = 110340004012.

The previous prime is 110340004003. The next prime is 110340004031. The reversal of 110340004013 is 310400043011.

Together with next prime (110340004031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73383017449 + 36956986564 = 270893^2 + 192242^2 .

It is a cyclic number.

It is not a de Polignac number, because 110340004013 - 2⁴ = 110340003997 is a prime.

It is a super-2 number, since 2×110340004013² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110340003982 and 110340004000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110340004003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55170002006 + 55170002007.

It is an arithmetic number, because the mean of its divisors is an integer number (55170002007).

Almost surely, 2^110340004013 is an apocalyptic number.

It is an amenable number.

110340004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

110340004013 is an equidigital number, since it uses as much as digits as its factorization.

110340004013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 110340004013 its reverse (310400043011), we get a palindrome (420740047024).

The spelling of 110340004013 in words is "one hundred ten billion, three hundred forty million, four thousand, thirteen".