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1103400321217 is a prime number
BaseRepresentation
bin10000000011100111110…
…010001100000011000001
310220111001212100222112121
4100003213302030003001
5121034230440234332
62202521202124241
7142501200660325
oct20034762140301
93814055328477
101103400321217
11395a49796717
12159a1a650681
13800863b436c
143b594d19985
151da7e26d797
hex100e7c8c0c1

1103400321217 has 2 divisors, whose sum is σ = 1103400321218. Its totient is φ = 1103400321216.

The previous prime is 1103400321209. The next prime is 1103400321251. The reversal of 1103400321217 is 7121230043011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 937161461041 + 166238860176 = 968071^2 + 407724^2 .

It is a cyclic number.

It is not a de Polignac number, because 1103400321217 - 23 = 1103400321209 is a prime.

It is a super-2 number, since 2×11034003212172 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1103400321191 and 1103400321200.

It is not a weakly prime, because it can be changed into another prime (1103410321217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551700160608 + 551700160609.

It is an arithmetic number, because the mean of its divisors is an integer number (551700160609).

Almost surely, 21103400321217 is an apocalyptic number.

It is an amenable number.

1103400321217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103400321217 is an equidigital number, since it uses as much as digits as its factorization.

1103400321217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 1103400321217 its reverse (7121230043011), we get a palindrome (8224630364228).

The spelling of 1103400321217 in words is "one trillion, one hundred three billion, four hundred million, three hundred twenty-one thousand, two hundred seventeen".