Base | Representation |
---|---|
bin | 10100100011010110… |
… | …11111000000101111 |
3 | 1001110222110210210111 |
4 | 22101223133000233 |
5 | 140044202431002 |
6 | 5022521320451 |
7 | 540301465021 |
oct | 122153370057 |
9 | 31428423714 |
10 | 11034030127 |
11 | 475247116a |
12 | 217b336127 |
13 | 106acb0b13 |
14 | 76960c011 |
15 | 448a623d7 |
hex | 291adf02f |
11034030127 has 2 divisors, whose sum is σ = 11034030128. Its totient is φ = 11034030126.
The previous prime is 11034030107. The next prime is 11034030173. The reversal of 11034030127 is 72103043011.
It is a weak prime.
It is an emirp because it is prime and its reverse (72103043011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11034030127 is a prime.
It is a super-2 number, since 2×110340301272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11034030098 and 11034030107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11034030107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5517015063 + 5517015064.
It is an arithmetic number, because the mean of its divisors is an integer number (5517015064).
Almost surely, 211034030127 is an apocalyptic number.
11034030127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11034030127 is an equidigital number, since it uses as much as digits as its factorization.
11034030127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 11034030127 its reverse (72103043011), we get a palindrome (83137073138).
The spelling of 11034030127 in words is "eleven billion, thirty-four million, thirty thousand, one hundred twenty-seven".
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