Base | Representation |
---|---|
bin | 10000000011101000100… |
… | …010100011011111000100 |
3 | 10220111002202020010202001 |
4 | 100003220202203133010 |
5 | 121034242212001012 |
6 | 2202522333555044 |
7 | 142501413515152 |
oct | 20035042433704 |
9 | 3814082203661 |
10 | 1103413000132 |
11 | 395a55966563 |
12 | 159a22945a84 |
13 | 80088c03391 |
14 | 3b59689a3d2 |
15 | 1da80425357 |
hex | 100e88a37c4 |
1103413000132 has 24 divisors (see below), whose sum is σ = 2037430989440. Its totient is φ = 521427805920.
The previous prime is 1103413000099. The next prime is 1103413000133. The reversal of 1103413000132 is 2310003143011.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is not an unprimeable number, because it can be changed into a prime (1103413000133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17210988 + ... + 17274979.
Almost surely, 21103413000132 is an apocalyptic number.
It is an amenable number.
1103413000132 is a deficient number, since it is larger than the sum of its proper divisors (934017989308).
1103413000132 is a wasteful number, since it uses less digits than its factorization.
1103413000132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34486411 (or 34486409 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1103413000132 its reverse (2310003143011), we get a palindrome (3413416143143).
The spelling of 1103413000132 in words is "one trillion, one hundred three billion, four hundred thirteen million, one hundred thirty-two", and thus it is an aban number.
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