Base | Representation |
---|---|
bin | 10000000011101000100… |
… | …111100101101110001111 |
3 | 10220111002211201012021121 |
4 | 100003220213211232033 |
5 | 121034243031220030 |
6 | 2202522422141411 |
7 | 142501430653210 |
oct | 20035047455617 |
9 | 3814084635247 |
10 | 1103414320015 |
11 | 395a56688177 |
12 | 159a23281867 |
13 | 80089276087 |
14 | 3b596b21407 |
15 | 1da805d647a |
hex | 100e89e5b8f |
1103414320015 has 32 divisors (see below), whose sum is σ = 1523814710400. Its totient is φ = 751349274624.
The previous prime is 1103414320003. The next prime is 1103414320049. The reversal of 1103414320015 is 5100234143011.
It is a cyclic number.
It is not a de Polignac number, because 1103414320015 - 29 = 1103414319503 is a prime.
It is a super-2 number, since 2×11034143200152 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21131179 + ... + 21183331.
It is an arithmetic number, because the mean of its divisors is an integer number (47619209700).
Almost surely, 21103414320015 is an apocalyptic number.
1103414320015 is a deficient number, since it is larger than the sum of its proper divisors (420400390385).
1103414320015 is a wasteful number, since it uses less digits than its factorization.
1103414320015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56371.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1103414320015 its reverse (5100234143011), we get a palindrome (6203648463026).
The spelling of 1103414320015 in words is "one trillion, one hundred three billion, four hundred fourteen million, three hundred twenty thousand, fifteen".
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