Base | Representation |
---|---|
bin | 10000000011101000100… |
… | …111111110001010010001 |
3 | 10220111002211220021120221 |
4 | 100003220213332022101 |
5 | 121034243042420423 |
6 | 2202522424233041 |
7 | 142501431551065 |
oct | 20035047761221 |
9 | 3814084807527 |
10 | 1103414420113 |
11 | 395a567463a5 |
12 | 159a2330b781 |
13 | 800892ac7c5 |
14 | 3b596b49aa5 |
15 | 1da80605e5d |
hex | 100e89fe291 |
1103414420113 has 2 divisors, whose sum is σ = 1103414420114. Its totient is φ = 1103414420112.
The previous prime is 1103414420099. The next prime is 1103414420189. The reversal of 1103414420113 is 3110244143011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1094235247249 + 9179172864 = 1046057^2 + 95808^2 .
It is a cyclic number.
It is not a de Polignac number, because 1103414420113 - 217 = 1103414289041 is a prime.
It is not a weakly prime, because it can be changed into another prime (1103414420413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551707210056 + 551707210057.
It is an arithmetic number, because the mean of its divisors is an integer number (551707210057).
Almost surely, 21103414420113 is an apocalyptic number.
It is an amenable number.
1103414420113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103414420113 is an equidigital number, since it uses as much as digits as its factorization.
1103414420113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1103414420113 its reverse (3110244143011), we get a palindrome (4213658563124).
The spelling of 1103414420113 in words is "one trillion, one hundred three billion, four hundred fourteen million, four hundred twenty thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.105 sec. • engine limits •