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1103434252471 is a prime number
BaseRepresentation
bin10000000011101001110…
…011101000000010110111
310220111011020012212110201
4100003221303220002313
5121034313132034341
62202524413301331
7142502062251265
oct20035163500267
93814136185421
101103434252471
11395a66961781
12159a29a94847
1380090434825
143b59962d435
151da82222331
hex100e9ce80b7

1103434252471 has 2 divisors, whose sum is σ = 1103434252472. Its totient is φ = 1103434252470.

The previous prime is 1103434252423. The next prime is 1103434252511. The reversal of 1103434252471 is 1742524343011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1103434252471 - 27 = 1103434252343 is a prime.

It is a super-3 number, since 3×11034342524713 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1103434252471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1103434256471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551717126235 + 551717126236.

It is an arithmetic number, because the mean of its divisors is an integer number (551717126236).

Almost surely, 21103434252471 is an apocalyptic number.

1103434252471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103434252471 is an equidigital number, since it uses as much as digits as its factorization.

1103434252471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80640, while the sum is 37.

Adding to 1103434252471 its reverse (1742524343011), we get a palindrome (2845958595482).

The spelling of 1103434252471 in words is "one trillion, one hundred three billion, four hundred thirty-four million, two hundred fifty-two thousand, four hundred seventy-one".