Base | Representation |
---|---|
bin | 10100100011110100… |
… | …11101011001101101 |
3 | 1001111020212020122211 |
4 | 22101322131121231 |
5 | 140101204040233 |
6 | 5023141410421 |
7 | 540350034562 |
oct | 122172353155 |
9 | 31436766584 |
10 | 11037955693 |
11 | 4754702536 |
12 | 2180709a11 |
13 | 106ba5683b |
14 | 769d50869 |
15 | 44908a5cd |
hex | 291e9d66d |
11037955693 has 2 divisors, whose sum is σ = 11037955694. Its totient is φ = 11037955692.
The previous prime is 11037955679. The next prime is 11037955711. The reversal of 11037955693 is 39655973011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9777847689 + 1260108004 = 98883^2 + 35498^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11037955693 is a prime.
It is a super-2 number, since 2×110379556932 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11037955633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5518977846 + 5518977847.
It is an arithmetic number, because the mean of its divisors is an integer number (5518977847).
Almost surely, 211037955693 is an apocalyptic number.
It is an amenable number.
11037955693 is a deficient number, since it is larger than the sum of its proper divisors (1).
11037955693 is an equidigital number, since it uses as much as digits as its factorization.
11037955693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 765450, while the sum is 49.
The spelling of 11037955693 in words is "eleven billion, thirty-seven million, nine hundred fifty-five thousand, six hundred ninety-three".
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