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11039345041 is a prime number
BaseRepresentation
bin10100100011111111…
…10000100110010001
31001111100110211111011
422101333300212101
5140102033020131
65023231250521
7540364612264
oct122177604621
931440424434
1011039345041
11475547135a
122181079a41
13106c12203a
1476a1d2cdb
154492620b1
hex291ff0991

11039345041 has 2 divisors, whose sum is σ = 11039345042. Its totient is φ = 11039345040.

The previous prime is 11039345033. The next prime is 11039345069. The reversal of 11039345041 is 14054393011.

11039345041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9642454416 + 1396890625 = 98196^2 + 37375^2 .

It is a cyclic number.

It is not a de Polignac number, because 11039345041 - 23 = 11039345033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11039344994 and 11039345012.

It is not a weakly prime, because it can be changed into another prime (11039345071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5519672520 + 5519672521.

It is an arithmetic number, because the mean of its divisors is an integer number (5519672521).

Almost surely, 211039345041 is an apocalyptic number.

It is an amenable number.

11039345041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11039345041 is an equidigital number, since it uses as much as digits as its factorization.

11039345041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

The spelling of 11039345041 in words is "eleven billion, thirty-nine million, three hundred forty-five thousand, forty-one".