Base | Representation |
---|---|
bin | 10100100100000101… |
… | …10000101110110111 |
3 | 1001111101221211000122 |
4 | 22102002300232313 |
5 | 140102233211043 |
6 | 5023300202155 |
7 | 540404400554 |
oct | 122202605667 |
9 | 31441854018 |
10 | 11040132023 |
11 | 4755959658 |
12 | 218139935b |
13 | 106c3392cb |
14 | 76a359a2b |
15 | 44936a368 |
hex | 2920b0bb7 |
11040132023 has 2 divisors, whose sum is σ = 11040132024. Its totient is φ = 11040132022.
The previous prime is 11040131933. The next prime is 11040132041. The reversal of 11040132023 is 32023104011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11040132023 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 11040131992 and 11040132010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11040135023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520066011 + 5520066012.
It is an arithmetic number, because the mean of its divisors is an integer number (5520066012).
Almost surely, 211040132023 is an apocalyptic number.
11040132023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040132023 is an equidigital number, since it uses as much as digits as its factorization.
11040132023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11040132023 its reverse (32023104011), we get a palindrome (43063236034).
The spelling of 11040132023 in words is "eleven billion, forty million, one hundred thirty-two thousand, twenty-three".
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