Base | Representation |
---|---|
bin | 11001000110100100010001… |
… | …001001110101000101001111 |
3 | 112110220100221121210021001011 |
4 | 121012210101021311011033 |
5 | 103432313130031224241 |
6 | 1030450101134430051 |
7 | 32153211640306165 |
oct | 3106442111650517 |
9 | 473810847707034 |
10 | 110402422133071 |
11 | 321a544a121a62 |
12 | 1047088b962327 |
13 | 497ab99677723 |
14 | 1d39711a85235 |
15 | cb6c48aa5281 |
hex | 64691127514f |
110402422133071 has 2 divisors, whose sum is σ = 110402422133072. Its totient is φ = 110402422133070.
The previous prime is 110402422132913. The next prime is 110402422133173. The reversal of 110402422133071 is 170331224204011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110402422133071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110402422137071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55201211066535 + 55201211066536.
It is an arithmetic number, because the mean of its divisors is an integer number (55201211066536).
Almost surely, 2110402422133071 is an apocalyptic number.
110402422133071 is a deficient number, since it is larger than the sum of its proper divisors (1).
110402422133071 is an equidigital number, since it uses as much as digits as its factorization.
110402422133071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 110402422133071 its reverse (170331224204011), we get a palindrome (280733646337082).
The spelling of 110402422133071 in words is "one hundred ten trillion, four hundred two billion, four hundred twenty-two million, one hundred thirty-three thousand, seventy-one".
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