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1104031412143 = 11100366492013
BaseRepresentation
bin10000000100001101011…
…001100110111110101111
310220112200211212201112121
4100010031121212332233
5121042024020142033
62203103544413411
7142522633110502
oct20041531467657
93815624781477
101104031412143
11396242a4a670
12159b75a77267
138015707764a
143b614a77139
151dab987d62d
hex1010d666faf

1104031412143 has 4 divisors (see below), whose sum is σ = 1204397904168. Its totient is φ = 1003664920120.

The previous prime is 1104031412137. The next prime is 1104031412177. The reversal of 1104031412143 is 3412141304011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1104031412143 - 217 = 1104031281071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1104031412243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50183245996 + ... + 50183246017.

It is an arithmetic number, because the mean of its divisors is an integer number (301099476042).

Almost surely, 21104031412143 is an apocalyptic number.

1104031412143 is a deficient number, since it is larger than the sum of its proper divisors (100366492025).

1104031412143 is a wasteful number, since it uses less digits than its factorization.

1104031412143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100366492024.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1104031412143 its reverse (3412141304011), we get a palindrome (4516172716154).

The spelling of 1104031412143 in words is "one trillion, one hundred four billion, thirty-one million, four hundred twelve thousand, one hundred forty-three".

Divisors: 1 11 100366492013 1104031412143