Base | Representation |
---|---|
bin | 10000000100001101100… |
… | …000111001111000001001 |
3 | 10220112200222110212212121 |
4 | 100010031200321320021 |
5 | 121042030012341203 |
6 | 2203104053411241 |
7 | 142522655264155 |
oct | 20041540717011 |
9 | 3815628425777 |
10 | 1104033324553 |
11 | 396244036475 |
12 | 159b76639b21 |
13 | 80157596c53 |
14 | 3b615014065 |
15 | 1dab9b0a0bd |
hex | 1010d839e09 |
1104033324553 has 2 divisors, whose sum is σ = 1104033324554. Its totient is φ = 1104033324552.
The previous prime is 1104033324533. The next prime is 1104033324599. The reversal of 1104033324553 is 3554233304011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1090378700944 + 13654623609 = 1044212^2 + 116853^2 .
It is a cyclic number.
It is not a de Polignac number, because 1104033324553 - 25 = 1104033324521 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104033324503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552016662276 + 552016662277.
It is an arithmetic number, because the mean of its divisors is an integer number (552016662277).
Almost surely, 21104033324553 is an apocalyptic number.
It is an amenable number.
1104033324553 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104033324553 is an equidigital number, since it uses as much as digits as its factorization.
1104033324553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 1104033324553 its reverse (3554233304011), we get a palindrome (4658266628564).
The spelling of 1104033324553 in words is "one trillion, one hundred four billion, thirty-three million, three hundred twenty-four thousand, five hundred fifty-three".
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