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1104040201373 is a prime number
BaseRepresentation
bin10000000100001101111…
…011001000110010011101
310220112201110102021002122
4100010031323020302131
5121042033242420443
62203104501032325
7142523100605204
oct20041573106235
93815643367078
101104040201373
11396247a0309a
12159b789b56a5
1380158b34085
143b615cc423b
151daba517968
hex1010dec8c9d

1104040201373 has 2 divisors, whose sum is σ = 1104040201374. Its totient is φ = 1104040201372.

The previous prime is 1104040201261. The next prime is 1104040201393. The reversal of 1104040201373 is 3731020404011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 558041868484 + 545998332889 = 747022^2 + 738917^2 .

It is an emirp because it is prime and its reverse (3731020404011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1104040201373 - 222 = 1104036007069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104040201393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552020100686 + 552020100687.

It is an arithmetic number, because the mean of its divisors is an integer number (552020100687).

Almost surely, 21104040201373 is an apocalyptic number.

It is an amenable number.

1104040201373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104040201373 is an equidigital number, since it uses as much as digits as its factorization.

1104040201373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 1104040201373 its reverse (3731020404011), we get a palindrome (4835060605384).

The spelling of 1104040201373 in words is "one trillion, one hundred four billion, forty million, two hundred one thousand, three hundred seventy-three".