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11041014121 is a prime number
BaseRepresentation
bin10100100100001100…
…01000000101101001
31001111110121122000221
422102012020011221
5140102444422441
65023331130041
7540415033354
oct122206100551
931443548027
1011041014121
114756401365
122181743921
13106c587967
1476a50929b
154494918d1
hex292188169

11041014121 has 2 divisors, whose sum is σ = 11041014122. Its totient is φ = 11041014120.

The previous prime is 11041014109. The next prime is 11041014163. The reversal of 11041014121 is 12141014011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10996458496 + 44555625 = 104864^2 + 6675^2 .

It is a cyclic number.

It is not a de Polignac number, because 11041014121 - 29 = 11041013609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11041014095 and 11041014104.

It is not a weakly prime, because it can be changed into another prime (11041014421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520507060 + 5520507061.

It is an arithmetic number, because the mean of its divisors is an integer number (5520507061).

Almost surely, 211041014121 is an apocalyptic number.

It is an amenable number.

11041014121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11041014121 is an equidigital number, since it uses as much as digits as its factorization.

11041014121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 11041014121 its reverse (12141014011), we get a palindrome (23182028132).

The spelling of 11041014121 in words is "eleven billion, forty-one million, fourteen thousand, one hundred twenty-one".