Search a number
-
+
110411251081 is a prime number
BaseRepresentation
bin110011011010100000…
…1011111110110001001
3101112222202020200210121
41212311001133312021
53302110240013311
6122420000143241
710656044102125
oct1466501376611
9345882220717
10110411251081
114290930013a
1219494607b21
13a54777a641
1454b5a76585
152d1327eb71
hex19b505fd89

110411251081 has 2 divisors, whose sum is σ = 110411251082. Its totient is φ = 110411251080.

The previous prime is 110411251001. The next prime is 110411251087. The reversal of 110411251081 is 180152114011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108955447056 + 1455804025 = 330084^2 + 38155^2 .

It is a cyclic number.

It is not a de Polignac number, because 110411251081 - 219 = 110410726793 is a prime.

It is a super-2 number, since 2×1104112510812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110411251087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55205625540 + 55205625541.

It is an arithmetic number, because the mean of its divisors is an integer number (55205625541).

Almost surely, 2110411251081 is an apocalyptic number.

It is an amenable number.

110411251081 is a deficient number, since it is larger than the sum of its proper divisors (1).

110411251081 is an equidigital number, since it uses as much as digits as its factorization.

110411251081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 320, while the sum is 25.

Adding to 110411251081 its reverse (180152114011), we get a palindrome (290563365092).

The spelling of 110411251081 in words is "one hundred ten billion, four hundred eleven million, two hundred fifty-one thousand, eighty-one".