11041131977 has 2 divisors, whose sum is σ = 11041131978. Its totient is φ = 11041131976.

The previous prime is 11041131961. The next prime is 11041131979. The reversal of 11041131977 is 77913114011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8665934281 + 2375197696 = 93091^2 + 48736^2 .

It is a cyclic number.

It is not a de Polignac number, because 11041131977 - 2⁴ = 11041131961 is a prime.

Together with 11041131979, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11041131979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520565988 + 5520565989.

It is an arithmetic number, because the mean of its divisors is an integer number (5520565989).

Almost surely, 2^11041131977 is an apocalyptic number.

It is an amenable number.

11041131977 is a deficient number, since it is larger than the sum of its proper divisors (1).

11041131977 is an equidigital number, since it uses as much as digits as its factorization.

11041131977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5292, while the sum is 35.

Adding to 11041131977 its reverse (77913114011), we get a palindrome (88954245988).

The spelling of 11041131977 in words is "eleven billion, forty-one million, one hundred thirty-one thousand, nine hundred seventy-seven".