Base | Representation |
---|---|
bin | 1010000010101011011011… |
… | …1000100110100011001111 |
3 | 1110002112002121222200022211 |
4 | 2200222312320212203033 |
5 | 2421344220331220444 |
6 | 35252121013051251 |
7 | 2216460412364161 |
oct | 240526670464317 |
9 | 43075077880284 |
10 | 11041134241999 |
11 | 357757848a834 |
12 | 12a3a19626b27 |
13 | 621236486014 |
14 | 2a2572636931 |
15 | 142312a3cc34 |
hex | a0ab6e268cf |
11041134241999 has 2 divisors, whose sum is σ = 11041134242000. Its totient is φ = 11041134241998.
The previous prime is 11041134241993. The next prime is 11041134242003. The reversal of 11041134241999 is 99914243114011.
11041134241999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11041134241999 - 237 = 10903695288527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11041134241993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520567120999 + 5520567121000.
It is an arithmetic number, because the mean of its divisors is an integer number (5520567121000).
Almost surely, 211041134241999 is an apocalyptic number.
11041134241999 is a deficient number, since it is larger than the sum of its proper divisors (1).
11041134241999 is an equidigital number, since it uses as much as digits as its factorization.
11041134241999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 49.
The spelling of 11041134241999 in words is "eleven trillion, forty-one billion, one hundred thirty-four million, two hundred forty-one thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •