Base | Representation |
---|---|
bin | 10000000100010100000… |
… | …111110111011001100001 |
3 | 10220112222201010000012021 |
4 | 100010110013313121201 |
5 | 121042241403420223 |
6 | 2203123054101441 |
7 | 142525502600056 |
oct | 20042407673141 |
9 | 3815881100167 |
10 | 1104144201313 |
11 | 3962a068685a |
12 | 159ba77aa881 |
13 | 801745483ba |
14 | 3b625a3702d |
15 | 1dac470c65d |
hex | 101141f7661 |
1104144201313 has 2 divisors, whose sum is σ = 1104144201314. Its totient is φ = 1104144201312.
The previous prime is 1104144201299. The next prime is 1104144201341. The reversal of 1104144201313 is 3131024414011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 750662822464 + 353481378849 = 866408^2 + 594543^2 .
It is a cyclic number.
It is not a de Polignac number, because 1104144201313 - 217 = 1104144070241 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104144201343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552072100656 + 552072100657.
It is an arithmetic number, because the mean of its divisors is an integer number (552072100657).
Almost surely, 21104144201313 is an apocalyptic number.
It is an amenable number.
1104144201313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104144201313 is an equidigital number, since it uses as much as digits as its factorization.
1104144201313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1104144201313 its reverse (3131024414011), we get a palindrome (4235168615324).
The spelling of 1104144201313 in words is "one trillion, one hundred four billion, one hundred forty-four million, two hundred one thousand, three hundred thirteen".
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