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1104144432331 is a prime number
BaseRepresentation
bin10000000100010100001…
…000101111110011001011
310220112222201112202002111
4100010110020233303023
5121042241433313311
62203123103043151
7142525504551433
oct20042410576313
93815881482074
101104144432331
113962a0824386
12159ba78a04b7
13801745c95b5
143b625a972c3
151dac4755d21
hex1011422fccb

1104144432331 has 2 divisors, whose sum is σ = 1104144432332. Its totient is φ = 1104144432330.

The previous prime is 1104144432329. The next prime is 1104144432337. The reversal of 1104144432331 is 1332344414011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1104144432331 - 21 = 1104144432329 is a prime.

It is a super-2 number, since 2×11041444323312 (a number of 25 digits) contains 22 as substring.

Together with 1104144432329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1104144432293 and 1104144432302.

It is not a weakly prime, because it can be changed into another prime (1104144432337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552072216165 + 552072216166.

It is an arithmetic number, because the mean of its divisors is an integer number (552072216166).

Almost surely, 21104144432331 is an apocalyptic number.

1104144432331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104144432331 is an equidigital number, since it uses as much as digits as its factorization.

1104144432331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1104144432331 its reverse (1332344414011), we get a palindrome (2436488846342).

The spelling of 1104144432331 in words is "one trillion, one hundred four billion, one hundred forty-four million, four hundred thirty-two thousand, three hundred thirty-one".