11042420133431 has 2 divisors, whose sum is σ = 11042420133432. Its totient is φ = 11042420133430.

The previous prime is 11042420133427. The next prime is 11042420133473. The reversal of 11042420133431 is 13433102424011.

It is a weak prime.

It is an emirp because it is prime and its reverse (13433102424011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11042420133431 - 2² = 11042420133427 is a prime.

It is a super-4 number, since 4×11042420133431⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11042420133394 and 11042420133403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11042420130431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521210066715 + 5521210066716.

It is an arithmetic number, because the mean of its divisors is an integer number (5521210066716).

Almost surely, 2^{11042420133431} is an apocalyptic number.

11042420133431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11042420133431 is an equidigital number, since it uses as much as digits as its factorization.

11042420133431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11042420133431 its reverse (13433102424011), we get a palindrome (24475522557442).

The spelling of 11042420133431 in words is "eleven trillion, forty-two billion, four hundred twenty million, one hundred thirty-three thousand, four hundred thirty-one".