1104300130049 has 2 divisors, whose sum is σ = 1104300130050. Its totient is φ = 1104300130048.

The previous prime is 1104300130027. The next prime is 1104300130051. The reversal of 1104300130049 is 9400310034011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 729560264449 + 374739865600 = 854143^2 + 612160^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1104300130049 is a prime.

Together with 1104300130051, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1104300130079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552150065024 + 552150065025.

It is an arithmetic number, because the mean of its divisors is an integer number (552150065025).

Almost surely, 2^{1104300130049} is an apocalyptic number.

It is an amenable number.

1104300130049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104300130049 is an equidigital number, since it uses as much as digits as its factorization.

1104300130049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 26.

The spelling of 1104300130049 in words is "one trillion, one hundred four billion, three hundred million, one hundred thirty thousand, forty-nine".