Base | Representation |
---|---|
bin | 10000000100011101100… |
… | …110000110001100010011 |
3 | 10220120101210010222020221 |
4 | 100010131212012030103 |
5 | 121043103044334141 |
6 | 2203150532213511 |
7 | 142532442440215 |
oct | 20043546061423 |
9 | 3816353128227 |
10 | 1104303121171 |
11 | 396372360688 |
12 | 15a030a6a297 |
13 | 8019b44b313 |
14 | 3b63cba45b5 |
15 | 1dad364ebd1 |
hex | 1011d986313 |
1104303121171 has 2 divisors, whose sum is σ = 1104303121172. Its totient is φ = 1104303121170.
The previous prime is 1104303121133. The next prime is 1104303121213. The reversal of 1104303121171 is 1711213034011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1104303121171 - 211 = 1104303119123 is a prime.
It is a super-2 number, since 2×11043031211712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1104303127171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552151560585 + 552151560586.
It is an arithmetic number, because the mean of its divisors is an integer number (552151560586).
Almost surely, 21104303121171 is an apocalyptic number.
1104303121171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104303121171 is an equidigital number, since it uses as much as digits as its factorization.
1104303121171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 1104303121171 its reverse (1711213034011), we get a palindrome (2815516155182).
The spelling of 1104303121171 in words is "one trillion, one hundred four billion, three hundred three million, one hundred twenty-one thousand, one hundred seventy-one".
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