110431121 has 2 divisors, whose sum is σ = 110431122. Its totient is φ = 110431120.

The previous prime is 110431117. The next prime is 110431127. The reversal of 110431121 is 121134011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57214096 + 53217025 = 7564^2 + 7295^2 .

It is a cyclic number.

It is not a de Polignac number, because 110431121 - 2² = 110431117 is a prime.

It is a super-3 number, since 3×110431121³ (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110431096 and 110431105.

It is not a weakly prime, because it can be changed into another prime (110431127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55215560 + 55215561.

It is an arithmetic number, because the mean of its divisors is an integer number (55215561).

Almost surely, 2^110431121 is an apocalyptic number.

It is an amenable number.

110431121 is a deficient number, since it is larger than the sum of its proper divisors (1).

110431121 is an equidigital number, since it uses as much as digits as its factorization.

110431121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 110431121 is about 10508.6212701762. The cubic root of 110431121 is about 479.7671338632.

Adding to 110431121 its reverse (121134011), we get a palindrome (231565132).

The spelling of 110431121 in words is "one hundred ten million, four hundred thirty-one thousand, one hundred twenty-one".