Base | Representation |
---|---|
bin | 10000000100011110010… |
… | …000011010011110110011 |
3 | 10220120102120000120012102 |
4 | 100010132100122132303 |
5 | 121043113414324243 |
6 | 2203152010051015 |
7 | 142532635641605 |
oct | 20043620323663 |
9 | 3816376016172 |
10 | 1104314214323 |
11 | 396378648081 |
12 | 15a034719a6b |
13 | 801a0833608 |
14 | 3b640451175 |
15 | 1dad45e19b8 |
hex | 1011e41a7b3 |
1104314214323 has 2 divisors, whose sum is σ = 1104314214324. Its totient is φ = 1104314214322.
The previous prime is 1104314214319. The next prime is 1104314214347. The reversal of 1104314214323 is 3234124134011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1104314214323 - 22 = 1104314214319 is a prime.
It is a super-5 number, since 5×11043142143235 (a number of 61 digits) contains 55555 as substring.
It is not a weakly prime, because it can be changed into another prime (1104314214623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552157107161 + 552157107162.
It is an arithmetic number, because the mean of its divisors is an integer number (552157107162).
Almost surely, 21104314214323 is an apocalyptic number.
1104314214323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104314214323 is an equidigital number, since it uses as much as digits as its factorization.
1104314214323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1104314214323 its reverse (3234124134011), we get a palindrome (4338438348334).
The spelling of 1104314214323 in words is "one trillion, one hundred four billion, three hundred fourteen million, two hundred fourteen thousand, three hundred twenty-three".
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