Base | Representation |
---|---|
bin | 10000000100011110010… |
… | …000011010011111001011 |
3 | 10220120102120000120020022 |
4 | 100010132100122133023 |
5 | 121043113414324342 |
6 | 2203152010051055 |
7 | 142532635641641 |
oct | 20043620323713 |
9 | 3816376016208 |
10 | 1104314214347 |
11 | 3963786480a3 |
12 | 15a034719a8b |
13 | 801a0833626 |
14 | 3b640451191 |
15 | 1dad45e19d2 |
hex | 1011e41a7cb |
1104314214347 has 2 divisors, whose sum is σ = 1104314214348. Its totient is φ = 1104314214346.
The previous prime is 1104314214323. The next prime is 1104314214349. The reversal of 1104314214347 is 7434124134011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1104314214347 - 210 = 1104314213323 is a prime.
Together with 1104314214349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1104314214349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552157107173 + 552157107174.
It is an arithmetic number, because the mean of its divisors is an integer number (552157107174).
Almost surely, 21104314214347 is an apocalyptic number.
1104314214347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104314214347 is an equidigital number, since it uses as much as digits as its factorization.
1104314214347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 1104314214347 its reverse (7434124134011), we get a palindrome (8538438348358).
The spelling of 1104314214347 in words is "one trillion, one hundred four billion, three hundred fourteen million, two hundred fourteen thousand, three hundred forty-seven".
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