Base | Representation |
---|---|
bin | 1010000010110011010101… |
… | …0100100100110101000111 |
3 | 1110002201120110111222000111 |
4 | 2200230311110210311013 |
5 | 2421413041402113244 |
6 | 35253111311053451 |
7 | 2216564110665112 |
oct | 240546524446507 |
9 | 43081513458014 |
10 | 11043255504199 |
11 | 3578466920496 |
12 | 12a430bb11287 |
13 | 6214b3aa9959 |
14 | 2a26d4259579 |
15 | 1423d8da4e34 |
hex | a0b35524d47 |
11043255504199 has 2 divisors, whose sum is σ = 11043255504200. Its totient is φ = 11043255504198.
The previous prime is 11043255504137. The next prime is 11043255504209. The reversal of 11043255504199 is 99140555234011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11043255504199 - 215 = 11043255471431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11043255504299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521627752099 + 5521627752100.
It is an arithmetic number, because the mean of its divisors is an integer number (5521627752100).
Almost surely, 211043255504199 is an apocalyptic number.
11043255504199 is a deficient number, since it is larger than the sum of its proper divisors (1).
11043255504199 is an equidigital number, since it uses as much as digits as its factorization.
11043255504199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 49.
The spelling of 11043255504199 in words is "eleven trillion, forty-three billion, two hundred fifty-five million, five hundred four thousand, one hundred ninety-nine".
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