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11043321122032 = 241793855908213
BaseRepresentation
bin1010000010110011100100…
…1110111000110011110000
31110002201202000222200202121
42200230321032320303300
52421413210201401112
635253122013324024
72216565535510543
oct240547116706360
943081660880677
1011043321122032
11357849a969101
1212a4329a96614
136214c4572984
142a26dcc5a85a
151423dea17407
hexa0b393b8cf0

11043321122032 has 20 divisors (see below), whose sum is σ = 21515967834120. Its totient is φ = 5490813293888.

The previous prime is 11043321121997. The next prime is 11043321122081. The reversal of 11043321122032 is 23022112334011.

It is a super-2 number, since 2×110433211220322 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11043321121988 and 11043321122006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1927951243 + ... + 1927956970.

It is an arithmetic number, because the mean of its divisors is an integer number (1075798391706).

Almost surely, 211043321122032 is an apocalyptic number.

It is an amenable number.

11043321122032 is a deficient number, since it is larger than the sum of its proper divisors (10472646712088).

11043321122032 is a wasteful number, since it uses less digits than its factorization.

11043321122032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3855908400 (or 3855908394 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11043321122032 its reverse (23022112334011), we get a palindrome (34065433456043).

The spelling of 11043321122032 in words is "eleven trillion, forty-three billion, three hundred twenty-one million, one hundred twenty-two thousand, thirty-two".

Divisors: 1 2 4 8 16 179 358 716 1432 2864 3855908213 7711816426 15423632852 30847265704 61694531408 690207570127 1380415140254 2760830280508 5521660561016 11043321122032