Base | Representation |
---|---|
bin | 10000000100011111010… |
… | …101110101100100010111 |
3 | 10220120110211021011101011 |
4 | 100010133111311210113 |
5 | 121043133044210312 |
6 | 2203153500113051 |
7 | 142533246426562 |
oct | 20043725654427 |
9 | 3816424234334 |
10 | 1104332413207 |
11 | 396387948181 |
12 | 15a03a835787 |
13 | 801a4535c9a |
14 | 3b642a2b4d9 |
15 | 1dad5ed8da7 |
hex | 1011f575917 |
1104332413207 has 2 divisors, whose sum is σ = 1104332413208. Its totient is φ = 1104332413206.
The previous prime is 1104332413169. The next prime is 1104332413237. The reversal of 1104332413207 is 7023142334011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1104332413207 - 215 = 1104332380439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1104332413237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552166206603 + 552166206604.
It is an arithmetic number, because the mean of its divisors is an integer number (552166206604).
Almost surely, 21104332413207 is an apocalyptic number.
1104332413207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104332413207 is an equidigital number, since it uses as much as digits as its factorization.
1104332413207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 1104332413207 its reverse (7023142334011), we get a palindrome (8127474747218).
The spelling of 1104332413207 in words is "one trillion, one hundred four billion, three hundred thirty-two million, four hundred thirteen thousand, two hundred seven".
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