Search a number
-
+
1104332413222 = 2552166206611
BaseRepresentation
bin10000000100011111010…
…101110101100100100110
310220120110211021011101201
4100010133111311210212
5121043133044210342
62203153500113114
7142533246426613
oct20043725654446
93816424234351
101104332413222
11396387948195
1215a03a83579a
13801a4535cac
143b642a2b50a
151dad5ed8db7
hex1011f575926

1104332413222 has 4 divisors (see below), whose sum is σ = 1656498619836. Its totient is φ = 552166206610.

The previous prime is 1104332413207. The next prime is 1104332413237. The reversal of 1104332413222 is 2223142334011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1104332413207) and next prime (1104332413237).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276083103304 + ... + 276083103307.

It is an arithmetic number, because the mean of its divisors is an integer number (414124654959).

Almost surely, 21104332413222 is an apocalyptic number.

1104332413222 is a deficient number, since it is larger than the sum of its proper divisors (552166206614).

1104332413222 is an equidigital number, since it uses as much as digits as its factorization.

1104332413222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 552166206613.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1104332413222 its reverse (2223142334011), we get a palindrome (3327474747233).

The spelling of 1104332413222 in words is "one trillion, one hundred four billion, three hundred thirty-two million, four hundred thirteen thousand, two hundred twenty-two".

Divisors: 1 2 552166206611 1104332413222