Search a number
-
+
11043331151 is a prime number
BaseRepresentation
bin10100100100011101…
…11101110001001111
31001111121222100101212
422102032331301033
5140104043044101
65023452525035
7540443523506
oct122216756117
931447870355
1011043331151
114757744166
12218248077b
13106cbb9498
1476a94d83d
1544979d1bb
hex2923bdc4f

11043331151 has 2 divisors, whose sum is σ = 11043331152. Its totient is φ = 11043331150.

The previous prime is 11043331129. The next prime is 11043331177. The reversal of 11043331151 is 15113334011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11043331151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11043333151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521665575 + 5521665576.

It is an arithmetic number, because the mean of its divisors is an integer number (5521665576).

Almost surely, 211043331151 is an apocalyptic number.

11043331151 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043331151 is an equidigital number, since it uses as much as digits as its factorization.

11043331151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 11043331151 its reverse (15113334011), we get a palindrome (26156665162).

The spelling of 11043331151 in words is "eleven billion, forty-three million, three hundred thirty-one thousand, one hundred fifty-one".