Base | Representation |
---|---|
bin | 10000000100011111011… |
… | …011111101110100010111 |
3 | 10220120110221021210021221 |
4 | 100010133123331310113 |
5 | 121043134002113423 |
6 | 2203153554351211 |
7 | 142533266200654 |
oct | 20043733756427 |
9 | 3816427253257 |
10 | 1104334019863 |
11 | 396388845298 |
12 | 15a03b28b507 |
13 | 801a4979379 |
14 | 3b642d28c2b |
15 | 1dad6204e5d |
hex | 1011f6fdd17 |
1104334019863 has 2 divisors, whose sum is σ = 1104334019864. Its totient is φ = 1104334019862.
The previous prime is 1104334019759. The next prime is 1104334019927. The reversal of 1104334019863 is 3689104334011.
It is a strong prime.
It is an emirp because it is prime and its reverse (3689104334011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1104334019863 - 225 = 1104300465431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1104334019263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552167009931 + 552167009932.
It is an arithmetic number, because the mean of its divisors is an integer number (552167009932).
Almost surely, 21104334019863 is an apocalyptic number.
1104334019863 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104334019863 is an equidigital number, since it uses as much as digits as its factorization.
1104334019863 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 43.
The spelling of 1104334019863 in words is "one trillion, one hundred four billion, three hundred thirty-four million, nineteen thousand, eight hundred sixty-three".
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