1104334020037 has 2 divisors, whose sum is σ = 1104334020038. Its totient is φ = 1104334020036.

The previous prime is 1104334020011. The next prime is 1104334020043. The reversal of 1104334020037 is 7300204334011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 591493275396 + 512840744641 = 769086^2 + 716129^2 .

It is an emirp because it is prime and its reverse (7300204334011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1104334020037 - 2¹¹ = 1104334017989 is a prime.

It is a super-2 number, since 2×1104334020037² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1104334019987 and 1104334020014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104337020037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552167010018 + 552167010019.

It is an arithmetic number, because the mean of its divisors is an integer number (552167010019).

Almost surely, 2^{1104334020037} is an apocalyptic number.

It is an amenable number.

1104334020037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104334020037 is an equidigital number, since it uses as much as digits as its factorization.

1104334020037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

Adding to 1104334020037 its reverse (7300204334011), we get a palindrome (8404538354048).

The spelling of 1104334020037 in words is "one trillion, one hundred four billion, three hundred thirty-four million, twenty thousand, thirty-seven".