Base | Representation |
---|---|
bin | 10000000100100000000… |
… | …010100000101001100001 |
3 | 10220120111122022010120021 |
4 | 100010200002200221201 |
5 | 121043144043432001 |
6 | 2203154555113441 |
7 | 142533451113046 |
oct | 20044002405141 |
9 | 3816448263507 |
10 | 1104344124001 |
11 | 396393516718 |
12 | 15a042742881 |
13 | 801a6aa6451 |
14 | 3b6443d91cd |
15 | 1dad704dba1 |
hex | 101200a0a61 |
1104344124001 has 2 divisors, whose sum is σ = 1104344124002. Its totient is φ = 1104344124000.
The previous prime is 1104344123957. The next prime is 1104344124011. The reversal of 1104344124001 is 1004214434011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 903353301601 + 200990822400 = 950449^2 + 448320^2 .
It is an emirp because it is prime and its reverse (1004214434011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1104344124001 - 211 = 1104344121953 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104344124011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552172062000 + 552172062001.
It is an arithmetic number, because the mean of its divisors is an integer number (552172062001).
Almost surely, 21104344124001 is an apocalyptic number.
It is an amenable number.
1104344124001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104344124001 is an equidigital number, since it uses as much as digits as its factorization.
1104344124001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1104344124001 its reverse (1004214434011), we get a palindrome (2108558558012).
The spelling of 1104344124001 in words is "one trillion, one hundred four billion, three hundred forty-four million, one hundred twenty-four thousand, one".
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