Base | Representation |
---|---|
bin | 1010000010110110110110… |
… | …1100111101110110101011 |
3 | 1110002211000101102120122102 |
4 | 2200231231230331312223 |
5 | 2421422011031003001 |
6 | 35253345221244015 |
7 | 2216626415110514 |
oct | 240555554756653 |
9 | 43084011376572 |
10 | 11044201422251 |
11 | 3578901865748 |
12 | 12a453486360b |
13 | 621604a5c78a |
14 | 2a2783b29a0b |
15 | 142441e51e6b |
hex | a0b6db3ddab |
11044201422251 has 2 divisors, whose sum is σ = 11044201422252. Its totient is φ = 11044201422250.
The previous prime is 11044201422239. The next prime is 11044201422253. The reversal of 11044201422251 is 15222410244011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11044201422251 is a prime.
It is a super-2 number, since 2×110442014222512 (a number of 27 digits) contains 22 as substring.
Together with 11044201422253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11044201422253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522100711125 + 5522100711126.
It is an arithmetic number, because the mean of its divisors is an integer number (5522100711126).
Almost surely, 211044201422251 is an apocalyptic number.
11044201422251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11044201422251 is an equidigital number, since it uses as much as digits as its factorization.
11044201422251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5120, while the sum is 29.
Adding to 11044201422251 its reverse (15222410244011), we get a palindrome (26266611666262).
The spelling of 11044201422251 in words is "eleven trillion, forty-four billion, two hundred one million, four hundred twenty-two thousand, two hundred fifty-one".
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