Base | Representation |
---|---|
bin | 1010000010111010010100… |
… | …0111110101111011001111 |
3 | 1110002220102011222220212222 |
4 | 2200232211013311323033 |
5 | 2421430412042331133 |
6 | 35254021354045555 |
7 | 2216661435161306 |
oct | 240564507657317 |
9 | 43086364886788 |
10 | 11045131214543 |
11 | 3579239696428 |
12 | 12a47541198bb |
13 | 62172258772a |
14 | 2a28313dd43d |
15 | 1424988b5e98 |
hex | a0ba51f5ecf |
11045131214543 has 2 divisors, whose sum is σ = 11045131214544. Its totient is φ = 11045131214542.
The previous prime is 11045131214477. The next prime is 11045131214567. The reversal of 11045131214543 is 34541213154011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11045131214543 - 228 = 11044862779087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11045131217543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522565607271 + 5522565607272.
It is an arithmetic number, because the mean of its divisors is an integer number (5522565607272).
Almost surely, 211045131214543 is an apocalyptic number.
11045131214543 is a deficient number, since it is larger than the sum of its proper divisors (1).
11045131214543 is an equidigital number, since it uses as much as digits as its factorization.
11045131214543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 11045131214543 its reverse (34541213154011), we get a palindrome (45586344368554).
The spelling of 11045131214543 in words is "eleven trillion, forty-five billion, one hundred thirty-one million, two hundred fourteen thousand, five hundred forty-three".
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