Base | Representation |
---|---|
bin | 10000000100101110000… |
… | …110110101110000001111 |
3 | 10220121010002101222201022 |
4 | 100010232012311300033 |
5 | 121044140003440142 |
6 | 2203234225504355 |
7 | 142542345163346 |
oct | 20045606656017 |
9 | 3817102358638 |
10 | 1104580140047 |
11 | 3964a4768aaa |
12 | 15a0a97a20bb |
13 | 80213960b07 |
14 | 3b6678b4b5d |
15 | 1daecb1e6d2 |
hex | 1012e1b5c0f |
1104580140047 has 2 divisors, whose sum is σ = 1104580140048. Its totient is φ = 1104580140046.
The previous prime is 1104580140043. The next prime is 1104580140061. The reversal of 1104580140047 is 7400410854011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1104580140047 - 22 = 1104580140043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1104580139989 and 1104580140016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1104580140043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552290070023 + 552290070024.
It is an arithmetic number, because the mean of its divisors is an integer number (552290070024).
Almost surely, 21104580140047 is an apocalyptic number.
1104580140047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104580140047 is an equidigital number, since it uses as much as digits as its factorization.
1104580140047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17920, while the sum is 35.
Adding to 1104580140047 its reverse (7400410854011), we get a palindrome (8504990994058).
The spelling of 1104580140047 in words is "one trillion, one hundred four billion, five hundred eighty million, one hundred forty thousand, forty-seven".
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