Base | Representation |
---|---|
bin | 1010000010111110000011… |
… | …1011000101010000000001 |
3 | 1110010000000002212020002112 |
4 | 2200233200323011100001 |
5 | 2421434440413034101 |
6 | 35254305114025105 |
7 | 2220025340034635 |
oct | 240574073052001 |
9 | 43100002766075 |
10 | 11046134502401 |
11 | 3579703a55449 |
12 | 12a4994118195 |
13 | 6218523a629b |
14 | 2a28c8764dc5 |
15 | 1425069e66bb |
hex | a0be0ec5401 |
11046134502401 has 2 divisors, whose sum is σ = 11046134502402. Its totient is φ = 11046134502400.
The previous prime is 11046134502341. The next prime is 11046134502457. The reversal of 11046134502401 is 10420543164011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9933212890000 + 1112921612401 = 3151700^2 + 1054951^2 .
It is a cyclic number.
It is not a de Polignac number, because 11046134502401 - 210 = 11046134501377 is a prime.
It is not a weakly prime, because it can be changed into another prime (11046134502101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5523067251200 + 5523067251201.
It is an arithmetic number, because the mean of its divisors is an integer number (5523067251201).
Almost surely, 211046134502401 is an apocalyptic number.
It is an amenable number.
11046134502401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11046134502401 is an equidigital number, since it uses as much as digits as its factorization.
11046134502401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 11046134502401 its reverse (10420543164011), we get a palindrome (21466677666412).
The spelling of 11046134502401 in words is "eleven trillion, forty-six billion, one hundred thirty-four million, five hundred two thousand, four hundred one".
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