Base | Representation |
---|---|
bin | 10100100101001110… |
… | …10110100000100111 |
3 | 1001112002000010122221 |
4 | 22102213112200213 |
5 | 140112212131233 |
6 | 5024241533211 |
7 | 540552050416 |
oct | 122247264047 |
9 | 31462003587 |
10 | 11049723943 |
11 | 4760310165 |
12 | 2184644207 |
13 | 10713171bb |
14 | 76b73547d |
15 | 44a11242d |
hex | 2929d6827 |
11049723943 has 2 divisors, whose sum is σ = 11049723944. Its totient is φ = 11049723942.
The previous prime is 11049723911. The next prime is 11049723947. The reversal of 11049723943 is 34932794011.
It is a strong prime.
It is an emirp because it is prime and its reverse (34932794011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11049723943 - 25 = 11049723911 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11049723943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11049723947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5524861971 + 5524861972.
It is an arithmetic number, because the mean of its divisors is an integer number (5524861972).
Almost surely, 211049723943 is an apocalyptic number.
11049723943 is a deficient number, since it is larger than the sum of its proper divisors (1).
11049723943 is an equidigital number, since it uses as much as digits as its factorization.
11049723943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 163296, while the sum is 43.
The spelling of 11049723943 in words is "eleven billion, forty-nine million, seven hundred twenty-three thousand, nine hundred forty-three".
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