Base | Representation |
---|---|
bin | 10000000101000111010… |
… | …111110010101101101111 |
3 | 10220122012122000001002011 |
4 | 100011013113302231233 |
5 | 121101022011430242 |
6 | 2203344250542051 |
7 | 142556013101644 |
oct | 20050727625557 |
9 | 3818178001064 |
10 | 1105004014447 |
11 | 3966a1a60123 |
12 | 15a1a7737927 |
13 | 80280711178 |
14 | 3b6a7cd1dcb |
15 | 1db24e4bd17 |
hex | 101475f2b6f |
1105004014447 has 2 divisors, whose sum is σ = 1105004014448. Its totient is φ = 1105004014446.
The previous prime is 1105004014379. The next prime is 1105004014451. The reversal of 1105004014447 is 7444104005011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1105004014447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1105004014487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552502007223 + 552502007224.
It is an arithmetic number, because the mean of its divisors is an integer number (552502007224).
Almost surely, 21105004014447 is an apocalyptic number.
1105004014447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1105004014447 is an equidigital number, since it uses as much as digits as its factorization.
1105004014447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8960, while the sum is 31.
Adding to 1105004014447 its reverse (7444104005011), we get a palindrome (8549108019458).
The spelling of 1105004014447 in words is "one trillion, one hundred five billion, four million, fourteen thousand, four hundred forty-seven".
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