1105011907 has 2 divisors, whose sum is σ = 1105011908. Its totient is φ = 1105011906.

The previous prime is 1105011871. The next prime is 1105011961. The reversal of 1105011907 is 7091105011.

It is a weak prime.

It is an emirp because it is prime and its reverse (7091105011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1105011907 - 2¹¹ = 1105009859 is a prime.

It is a super-2 number, since 2×1105011907² = 2442102629223553298, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1105011967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552505953 + 552505954.

It is an arithmetic number, because the mean of its divisors is an integer number (552505954).

Almost surely, 2^1105011907 is an apocalyptic number.

1105011907 is a deficient number, since it is larger than the sum of its proper divisors (1).

1105011907 is an equidigital number, since it uses as much as digits as its factorization.

1105011907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 315, while the sum is 25.

The square root of 1105011907 is about 33241.7193749060. The cubic root of 1105011907 is about 1033.8455258113.

Adding to 1105011907 its reverse (7091105011), we get a palindrome (8196116918).

The spelling of 1105011907 in words is "one billion, one hundred five million, eleven thousand, nine hundred seven".