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11050143121 is a prime number
BaseRepresentation
bin10100100101010001…
…11100110110010001
31001112002210102200001
422102220330312101
5140112314034441
65024254530001
7540555444463
oct122250746621
931462712601
1011050143121
114760577096
122184806901
131071432c34
1476b804133
1544a196731
hex292a3cd91

11050143121 has 2 divisors, whose sum is σ = 11050143122. Its totient is φ = 11050143120.

The previous prime is 11050143119. The next prime is 11050143173. The reversal of 11050143121 is 12134105011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9094292496 + 1955850625 = 95364^2 + 44225^2 .

It is a cyclic number.

It is not a de Polignac number, because 11050143121 - 21 = 11050143119 is a prime.

Together with 11050143119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11050140121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525071560 + 5525071561.

It is an arithmetic number, because the mean of its divisors is an integer number (5525071561).

Almost surely, 211050143121 is an apocalyptic number.

It is an amenable number.

11050143121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11050143121 is an equidigital number, since it uses as much as digits as its factorization.

11050143121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 11050143121 its reverse (12134105011), we get a palindrome (23184248132).

The spelling of 11050143121 in words is "eleven billion, fifty million, one hundred forty-three thousand, one hundred twenty-one".