Base | Representation |
---|---|
bin | 1010000011001101101111… |
… | …1001010111010101100011 |
3 | 1110010101212112220102222012 |
4 | 2200303123321113111203 |
5 | 2422022101323232121 |
6 | 35300243010303135 |
7 | 2220234565564043 |
oct | 240633371272543 |
9 | 43111775812865 |
10 | 11050345133411 |
11 | 3580474822891 |
12 | 12a576a287aab |
13 | 622073834b1c |
14 | 2a2ba7a67723 |
15 | 1426a14c5c5b |
hex | a0cdbe57563 |
11050345133411 has 2 divisors, whose sum is σ = 11050345133412. Its totient is φ = 11050345133410.
The previous prime is 11050345133363. The next prime is 11050345133441. The reversal of 11050345133411 is 11433154305011.
It is a strong prime.
It is an emirp because it is prime and its reverse (11433154305011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11050345133411 - 222 = 11050340939107 is a prime.
It is a super-2 number, since 2×110503451334112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11050345133441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525172566705 + 5525172566706.
It is an arithmetic number, because the mean of its divisors is an integer number (5525172566706).
Almost surely, 211050345133411 is an apocalyptic number.
11050345133411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11050345133411 is an equidigital number, since it uses as much as digits as its factorization.
11050345133411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 11050345133411 its reverse (11433154305011), we get a palindrome (22483499438422).
The spelling of 11050345133411 in words is "eleven trillion, fifty billion, three hundred forty-five million, one hundred thirty-three thousand, four hundred eleven".
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