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11050505099951 is a prime number
BaseRepresentation
bin1010000011001110010101…
…1011100101101010101111
31110010102021200220120210212
42200303211123211222233
52422022413301144301
635300310523053035
72220241550353562
oct240634533455257
943112250816725
1011050505099951
113580547052039
1212a57b397117b
1362209aa13295
142a2bc0dc84d9
151426b05734bb
hexa0ce56e5aaf

11050505099951 has 2 divisors, whose sum is σ = 11050505099952. Its totient is φ = 11050505099950.

The previous prime is 11050505099941. The next prime is 11050505100059. The reversal of 11050505099951 is 15999050505011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11050505099951 is a prime.

It is a super-2 number, since 2×110505050999512 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11050505099951.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11050505099941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525252549975 + 5525252549976.

It is an arithmetic number, because the mean of its divisors is an integer number (5525252549976).

Almost surely, 211050505099951 is an apocalyptic number.

11050505099951 is a deficient number, since it is larger than the sum of its proper divisors (1).

11050505099951 is an equidigital number, since it uses as much as digits as its factorization.

11050505099951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 455625, while the sum is 50.

The spelling of 11050505099951 in words is "eleven trillion, fifty billion, five hundred five million, ninety-nine thousand, nine hundred fifty-one".