Base | Representation |
---|---|
bin | 1010000011010010100101… |
… | …0101101110011011010010 |
3 | 1110010112020002201201101112 |
4 | 2200310221111232123102 |
5 | 2422032231432214100 |
6 | 35301015542333322 |
7 | 2220312023356061 |
oct | 240645125563322 |
9 | 43115202651345 |
10 | 11051644413650 |
11 | 3580a81179305 |
12 | 12a5a7142a242 |
13 | 62221ca7a2b9 |
14 | 2a2c8c43c1d8 |
15 | 14272a5c2b35 |
hex | a0d2956e6d2 |
11051644413650 has 12 divisors (see below), whose sum is σ = 20556058609482. Its totient is φ = 4420657765440.
The previous prime is 11051644413613. The next prime is 11051644413673. The reversal of 11051644413650 is 5631444615011.
It can be written as a sum of positive squares in 3 ways, for example, as 9335169733201 + 1716474680449 = 3055351^2 + 1310143^2 .
It is a super-2 number, since 2×110516444136502 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11051644413598 and 11051644413607.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 110516444087 + ... + 110516444186.
Almost surely, 211051644413650 is an apocalyptic number.
11051644413650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11051644413650 is a deficient number, since it is larger than the sum of its proper divisors (9504414195832).
11051644413650 is a wasteful number, since it uses less digits than its factorization.
11051644413650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 221032888285 (or 221032888280 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 11051644413650 in words is "eleven trillion, fifty-one billion, six hundred forty-four million, four hundred thirteen thousand, six hundred fifty".
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