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11051666365549 is a prime number
BaseRepresentation
bin1010000011010010101010…
…1001011101110001101101
31110010112021122000222201211
42200310222221131301231
52422032303042144144
635301022045034421
72220312411064555
oct240645251356155
943115248028654
1011051666365549
113580a92602077
1212a5a78855a11
13622224494ca4
142a2c91314165
1514272c4ac034
hexa0d2aa5dc6d

11051666365549 has 2 divisors, whose sum is σ = 11051666365550. Its totient is φ = 11051666365548.

The previous prime is 11051666365489. The next prime is 11051666365559. The reversal of 11051666365549 is 94556366615011.

11051666365549 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8991631946025 + 2060034419524 = 2998605^2 + 1435282^2 .

It is a cyclic number.

It is not a de Polignac number, because 11051666365549 - 223 = 11051657976941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11051666365493 and 11051666365502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11051666365559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525833182774 + 5525833182775.

It is an arithmetic number, because the mean of its divisors is an integer number (5525833182775).

Almost surely, 211051666365549 is an apocalyptic number.

It is an amenable number.

11051666365549 is a deficient number, since it is larger than the sum of its proper divisors (1).

11051666365549 is an equidigital number, since it uses as much as digits as its factorization.

11051666365549 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496000, while the sum is 58.

The spelling of 11051666365549 in words is "eleven trillion, fifty-one billion, six hundred sixty-six million, three hundred sixty-five thousand, five hundred forty-nine".