Base | Representation |
---|---|
bin | 110011011101110000… |
… | …1101010000100101001 |
3 | 101120021100112020100102 |
4 | 1212323201222010221 |
5 | 3302321202013443 |
6 | 122434454315145 |
7 | 10661540300621 |
oct | 1467341520451 |
9 | 346240466312 |
10 | 110520344873 |
11 | 429649429a4 |
12 | 19505058ab5 |
13 | a564256393 |
14 | 54c6353881 |
15 | 2d1cb2dcb8 |
hex | 19bb86a129 |
110520344873 has 2 divisors, whose sum is σ = 110520344874. Its totient is φ = 110520344872.
The previous prime is 110520344821. The next prime is 110520344951. The reversal of 110520344873 is 378443025011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 56132507929 + 54387836944 = 236923^2 + 233212^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110520344873 is a prime.
It is a super-2 number, since 2×1105203448732 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110520349873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55260172436 + 55260172437.
It is an arithmetic number, because the mean of its divisors is an integer number (55260172437).
Almost surely, 2110520344873 is an apocalyptic number.
It is an amenable number.
110520344873 is a deficient number, since it is larger than the sum of its proper divisors (1).
110520344873 is an equidigital number, since it uses as much as digits as its factorization.
110520344873 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 38.
Adding to 110520344873 its reverse (378443025011), we get a palindrome (488963369884).
The spelling of 110520344873 in words is "one hundred ten billion, five hundred twenty million, three hundred forty-four thousand, eight hundred seventy-three".
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