Base | Representation |
---|---|
bin | 101010001010… |
… | …100101111001 |
3 | 202210120110102 |
4 | 222022211321 |
5 | 10312202213 |
6 | 1032525145 |
7 | 162644516 |
oct | 52124571 |
9 | 22716412 |
10 | 11053433 |
11 | 626a676 |
12 | 38507b5 |
13 | 23a01c1 |
14 | 167a30d |
15 | e85158 |
hex | a8a979 |
11053433 has 2 divisors, whose sum is σ = 11053434. Its totient is φ = 11053432.
The previous prime is 11053411. The next prime is 11053447. The reversal of 11053433 is 33435011.
It is a happy number.
11053433 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8779369 + 2274064 = 2963^2 + 1508^2 .
It is an emirp because it is prime and its reverse (33435011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11053433 - 26 = 11053369 is a prime.
It is not a weakly prime, because it can be changed into another prime (11058433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526716 + 5526717.
It is an arithmetic number, because the mean of its divisors is an integer number (5526717).
Almost surely, 211053433 is an apocalyptic number.
It is an amenable number.
11053433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11053433 is an equidigital number, since it uses as much as digits as its factorization.
11053433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 20.
The square root of 11053433 is about 3324.6703595996. The cubic root of 11053433 is about 222.7575303661.
Adding to 11053433 its reverse (33435011), we get a palindrome (44488444).
The spelling of 11053433 in words is "eleven million, fifty-three thousand, four hundred thirty-three".
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